/* * Code for simulating pthreads API on Windows. This is Git-specific, * but it is enough for Numexpr needs too. * * Copyright (C) 2009 Andrzej K. Haczewski * * Permission is hereby granted, free of charge, to any person obtaining a copy * of this software and associated documentation files (the "Software"), to deal * in the Software without restriction, including without limitation the rights * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell * copies of the Software, and to permit persons to whom the Software is * furnished to do so, subject to the following conditions: * * The above copyright notice and this permission notice shall be included in * all copies or substantial portions of the Software. * * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN * THE SOFTWARE. * * DISCLAIMER: The implementation is Git-specific, it is subset of original * Pthreads API, without lots of other features that Git doesn't use. * Git also makes sure that the passed arguments are valid, so there's * no need for double-checking. */ #include "pthread.h" #include #include #include #include #include void die(const char *err, ...) { printf("%s", err); exit(-1); } static unsigned __stdcall win32_start_routine(void *arg) { pthread_t *thread = (pthread_t*)arg; thread->arg = thread->start_routine(thread->arg); return 0; } int pthread_create(pthread_t *thread, const void *unused, void *(*start_routine)(void*), void *arg) { thread->arg = arg; thread->start_routine = start_routine; thread->handle = (HANDLE) _beginthreadex(NULL, 0, win32_start_routine, thread, 0, NULL); if (!thread->handle) return errno; else return 0; } int win32_pthread_join(pthread_t *thread, void **value_ptr) { DWORD result = WaitForSingleObject(thread->handle, INFINITE); switch (result) { case WAIT_OBJECT_0: if (value_ptr) *value_ptr = thread->arg; return 0; case WAIT_ABANDONED: return EINVAL; default: return GetLastError(); } } int pthread_cond_init(pthread_cond_t *cond, const void *unused) { cond->waiters = 0; cond->was_broadcast = 0; InitializeCriticalSection(&cond->waiters_lock); cond->sema = CreateSemaphore(NULL, 0, LONG_MAX, NULL); if (!cond->sema) die("CreateSemaphore() failed"); cond->continue_broadcast = CreateEvent(NULL, /* security */ FALSE, /* auto-reset */ FALSE, /* not signaled */ NULL); /* name */ if (!cond->continue_broadcast) die("CreateEvent() failed"); return 0; } int pthread_cond_destroy(pthread_cond_t *cond) { CloseHandle(cond->sema); CloseHandle(cond->continue_broadcast); DeleteCriticalSection(&cond->waiters_lock); return 0; } int pthread_cond_wait(pthread_cond_t *cond, CRITICAL_SECTION *mutex) { int last_waiter; EnterCriticalSection(&cond->waiters_lock); cond->waiters++; LeaveCriticalSection(&cond->waiters_lock); /* * Unlock external mutex and wait for signal. * NOTE: we've held mutex locked long enough to increment * waiters count above, so there's no problem with * leaving mutex unlocked before we wait on semaphore. */ LeaveCriticalSection(mutex); /* let's wait - ignore return value */ WaitForSingleObject(cond->sema, INFINITE); /* * Decrease waiters count. If we are the last waiter, then we must * notify the broadcasting thread that it can continue. * But if we continued due to cond_signal, we do not have to do that * because the signaling thread knows that only one waiter continued. */ EnterCriticalSection(&cond->waiters_lock); cond->waiters--; last_waiter = cond->was_broadcast && cond->waiters == 0; LeaveCriticalSection(&cond->waiters_lock); if (last_waiter) { /* * cond_broadcast was issued while mutex was held. This means * that all other waiters have continued, but are contending * for the mutex at the end of this function because the * broadcasting thread did not leave cond_broadcast, yet. * (This is so that it can be sure that each waiter has * consumed exactly one slice of the semaphor.) * The last waiter must tell the broadcasting thread that it * can go on. */ SetEvent(cond->continue_broadcast); /* * Now we go on to contend with all other waiters for * the mutex. Auf in den Kampf! */ } /* lock external mutex again */ EnterCriticalSection(mutex); return 0; } /* * IMPORTANT: This implementation requires that pthread_cond_signal * is called while the mutex is held that is used in the corresponding * pthread_cond_wait calls! */ int pthread_cond_signal(pthread_cond_t *cond) { int have_waiters; EnterCriticalSection(&cond->waiters_lock); have_waiters = cond->waiters > 0; LeaveCriticalSection(&cond->waiters_lock); /* * Signal only when there are waiters */ if (have_waiters) return ReleaseSemaphore(cond->sema, 1, NULL) ? 0 : GetLastError(); else return 0; } /* * DOUBLY IMPORTANT: This implementation requires that pthread_cond_broadcast * is called while the mutex is held that is used in the corresponding * pthread_cond_wait calls! */ int pthread_cond_broadcast(pthread_cond_t *cond) { EnterCriticalSection(&cond->waiters_lock); if ((cond->was_broadcast = cond->waiters > 0)) { /* wake up all waiters */ ReleaseSemaphore(cond->sema, cond->waiters, NULL); LeaveCriticalSection(&cond->waiters_lock); /* * At this point all waiters continue. Each one takes its * slice of the semaphor. Now it's our turn to wait: Since * the external mutex is held, no thread can leave cond_wait, * yet. For this reason, we can be sure that no thread gets * a chance to eat *more* than one slice. OTOH, it means * that the last waiter must send us a wake-up. */ WaitForSingleObject(cond->continue_broadcast, INFINITE); /* * Since the external mutex is held, no thread can enter * cond_wait, and, hence, it is safe to reset this flag * without cond->waiters_lock held. */ cond->was_broadcast = 0; } else { LeaveCriticalSection(&cond->waiters_lock); } return 0; }